El segment circular

sinα = 3.5/5 = 0,7  per tant  α = 44,427º

te àrea  2α*πr2/360º = 19.384937 ..

h = altura triangle = 3,57 cm.

Area triangle = b*h/2 =  3,57* 7 / 2 =  12,495 cm2

El segment circular s'obte restant les dues àrees calculades

O = (2.37, 0.07)
a = 5
c = Circle(O, a)
A = Point(c)
B = Point(c)
b = Segment(A, B)
P, b_1, o, a_1 = Polygon(O, A, B)
d = OrthogonalLine(O, b)
C = Intersect(d, b)
α = Angle(C, O, B)
h = Distance(C, O)